probability= (6c1 + 11c1 )/ 51c1 = .3333

isn't this correct solution??

isn't this correct solution??

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blind00x
asked
in Probability
Apr 22, 2018

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4 votes

Best answer

Uniform random variable X with parameter a,b:

F(X)=$\frac{1}{b-a}$

F(X)=2 ,a=.5 and b= 1.

To find probability distribution of the interval (0.55,0.60) and (0.75 , 0.85), find the area of the region they cover.

Probability (X)= area 1 + area 2

area 1 :- As it will make rectangle with height=2 and width=0.60-0.55=0.05. Area1= 0.05*2=0.1

area 2 :-

As it will make rectangle with height=2 and width=0.85-0.75=0.1. Area1= 0.1*2=0.2

Probability = 0.1+0.2=0.3

https://en.wikipedia.org/wiki/Uniform_distribution_(continuous)