1 votes 1 votes Given two sorted list of size $m$ and $n$ respectively. The number of comparisons needed the worst case by the merge sort algorithm will be: $m \times n$ maximum of $m$ and $n$ minimum of $m$ and $n$ $m+n-1$ Algorithms isro2018 algorithms merge-sort + – Arjun asked Apr 22, 2018 • edited Jan 24 by makhdoom ghaya Arjun 2.4k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 3 votes 3 votes option d worst case comparisons in merge sort is o(m+n-1) abhishekmehta4u answered Apr 22, 2018 • selected Apr 23, 2018 by ManojK abhishekmehta4u comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments Abhishek Chavle commented Aug 5, 2021 reply Follow Share How many for best case ?? 1 votes 1 votes Answers Copied commented Sep 21, 2023 reply Follow Share min(m,n) 0 votes 0 votes Vijay Devagonda commented Dec 26, 2023 reply Follow Share It depends , either max(m,n) or min(m,n) . Out of these two cases , one of the answer is possible and which one is to choose out of these two is completely depends on particular arrays . 0 votes 0 votes Please log in or register to add a comment.