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Best answer
11 votes
11 votes

Let the no. of digits occupied by the ternary system be 'x'

Now,Maxi. value representable in ternary system using x digits = Maxi. value representable in binary system using  n digits

3x-1=2n-1

x=log32n = n log32   (d)

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18 votes
18 votes

Maximum No. possible using n-bit in Binary:- 2n -1

Maximum no. possible using x bit in Ternary:- 3x -1

Both will take different no. of bits to represent same number. 

3x -1 =  2n -1

3=  2n

taking log on both side:;-

X= log3 ( 2 )

X=n*log32 .

Answer:

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