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ISRO2018-19

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Given $\sqrt{224_{r}}$= $13$$_{r}$ the value of radix $r$ is

  1. $10$
  2. $8$
  3. $6$
  4. $5$
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Given $\sqrt(224)_{r}=13_{r}$

$2r^{2}+2r+4=(r+3)^{2}$

$2r^{2}+2r+4=r^{2}+9+6r$

$r^{2}-4r-5=0$

$r=5,-1$

Only $5$ is possible

Hence option d) is correct

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Given $\sqrt(224)_{r}=13_{r}$

$2r^{2}+2r+4=(r+3)^{2}$

$2r^{2}+2r+4=r^{2}+9+6r$

$r^{2}-4r-5=0$

$r=5,-1$

Only $5$ is possible

Hence option d) is correct

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