Sizeof Operator

Question

Q)What is the output of the following C program fragment?Assume size of an integer is 4 Bytes

#include<stdio.h>

int main()

{

int i = 5;

int var = sizeof( i++);

printf("%d %d",i ,var);

return 0;

}

 

A) 5 4          B) 6 4          C) 5 8                D)Compiler Error

Answer 1

int i=5

int var= sizeof(i++);

But sizeof(variable), variable will not be evaluated until it is variable length array type.

so i++ will not be incremented
==>> as sizeof is compile time operator so during compilation value will be generated and hence not evaluted during run time
answer:- 5,4

https://stackoverflow.com/questions/8225776/why-does-sizeofx-not-increment-x

Thanks srestha for corrrection

Comments

it is giving 5,4

https://ideone.com/U5PuW9

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sorry, i thought it is simple c program. Thank you for commenting

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@srestha and @sonveer

Please can you explain what does it mean size of is compile time operator so value will be generated at compile time not run time . Please suggest.

Thanks