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25 votes
25 votes

Consider the matrix as given below.

$$\begin{bmatrix} 1 & 2 & 3 \\  0 & 4 & 7 \\  0 & 0 & 3\end{bmatrix}$$

Which one of the following options provides the CORRECT values of the eigenvalues of the matrix?

  1. $1, 4, 3$
  2. $3, 7, 3$
  3. $7, 3, 2$
  4. $1, 2, 3$
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5 Answers

Best answer
32 votes
32 votes
The answer is $A.$

The given matrix is an upper triangular matrix and the eigenvalues of upper or lower triangular matrix are

the diagonal values itself.(Property)
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9 votes
9 votes
another method is also very shortcut $\begin{vmatrix} 1-\lambda &2 &3 \\ 0 &4-\lambda &7 \\ 0& 0 &3-\lambda \end{vmatrix}$

now to find Eigen values we calculate determinant of matrix and we calculate determinant along 1st column which give

$(1-\lambda )(4-\lambda )(3-\lambda )=0$    which gives $\lambda =1,3,4$
4 votes
4 votes

it should follow two conditions 

1-Trace of matrix = sum of Eigen Values =sum of diagonal

Trace=1+4+3=8

2 -Determinant of given matrix = 12 

As we know product of eigen values is determinant of matrix 

Now we have to check options 

(A) 1, 4, 3 =1+4+3=8 satisfied

(B) 3, 7, 3 =3+7+3=13 Wrong

(C) 7, 3, 2 =7+3+7=17 Wrong

(D) 1, 2, 3 =1+2+3=6 Wrong

So option A is answer

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