279 views
1 votes
1 votes
#include<stdio.h>
main()
{
int a[][3] = {1, 2, 3, 4, 5, 6};
int (*ptr)[3] = a;
printf("%d %d ", (*ptr)[1], (*ptr)[2]);
++ptr;
printf("%d %d\n", (*ptr)[1], (*ptr)[2]);
return 0;
}

explain this program?

1 Answer

Best answer
4 votes
4 votes

${\color{Red} {int (*ptr)[3]} } \rightarrow$ This is a pointer to an array of $3 \ integers$

${\color{Blue} {int (*ptr)[3] = a}} \rightarrow$    it stores address of $a$ .

${\color{Blue} {(*ptr)[1] }} \rightarrow$   it is $a[0][1]$ which is $2$

${\color{Blue} {(*ptr)[2] }} \rightarrow$    it is $a[0][2]$ which is $3$

${\color{Blue} {(++ptr) }} \rightarrow$it is  increased .it accesses  to $2^{nd}$ row of the  array 

${\color{Blue} {(*ptr)[1] }} \rightarrow$   it is $a[1][1]$ which is $5$

${\color{Blue} {(*ptr)[2] }} \rightarrow$    it is $a[1][2]$ which is $6$

selected by

Related questions

0 votes
0 votes
1 answer
1
SSR17 asked Feb 29
204 views
#include <stdio.h int main() { int i = -1; int x = (unsigned char)i; printf("%d", x); return 0; }output is 255 , but please explain how
2 votes
2 votes
1 answer
2
rupamsardar asked Aug 30, 2023
466 views
#include <stdio.h int f(int x) { if(x%2==0) { return f(f(x-1)); } else return (x++); } int main() { printf("%d",f(12)); ret...
5 votes
5 votes
2 answers
3
saurabh0709 asked Aug 1, 2023
1,136 views
What will be the output of the following code? _______ #include <stdio.h int main(){ char val=250; int ans; ans= val+ !val + ~val + ++val; printf("%d", ans); return 0; }
2 votes
2 votes
1 answer
4