+1 vote
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Suppose, In Selective Repeat Protocol 10 packets are sent and every 4th packet is lost.

Then, 1 2 3 4 4 5 6 7 7 8 9 10 10  {bold denote lost packets, so retransmitted!}

Is this the right order of transmission of packet no.??

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Yes, it is right.
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Order may differ..Lost packet will be resent after its time out at sender side

But it is sure that only Lost packet will be retransmitted!
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This question needs more clarification with regards to the window size.. Otherwise, its no different to a window size of 4 in Go-Back-N.

The lost packets will be retransmitted after getting the respective ACKs. So the correct order should be 123456789104710 right ?
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Order may vary but yes lost packets 4 7 10 will be retransmitted. Retransmission of packet will be done when sender does not found ACK till it's Time Out.
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Assuming that the transmission of the lost packets happens at the end (i.e., after the sender has finished transmitting all its packets), then can we have the following order ? (Packets given in italicized and bold indicate the lost packets.)

1 2 3 4 5 6 7 8 9 10 4 8 8

Every 4th packet is getting dropped (4, 8 and 8)..

+1 vote