1 votes 1 votes Suppose, In Selective Repeat Protocol 10 packets are sent and every 4th packet is lost. Then, 1 2 3 4 4 5 6 7 7 8 9 10 10 {bold denote lost packets, so retransmitted!} Is this the right order of transmission of packet no.?? Computer Networks computer-networks sliding-window selective-repeat + – Naveen Kumar 3 asked May 8, 2018 Naveen Kumar 3 1.3k views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Akhilesh Singla commented May 8, 2018 reply Follow Share Yes, it is right. 1 votes 1 votes Naveen Kumar 3 commented May 8, 2018 reply Follow Share Order may differ..Lost packet will be resent after its time out at sender side But it is sure that only Lost packet will be retransmitted! 0 votes 0 votes the_bob commented Sep 2, 2018 i edited by the_bob Sep 2, 2018 reply Follow Share This question needs more clarification with regards to the window size.. Otherwise, its no different to a window size of 4 in Go-Back-N. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes The lost packets will be retransmitted after getting the respective ACKs. So the correct order should be 123456789104710 right ? oldDoctor answered May 9, 2018 oldDoctor comment Share Follow See all 2 Comments See all 2 2 Comments reply Naveen Kumar 3 commented May 9, 2018 reply Follow Share Order may vary but yes lost packets 4 7 10 will be retransmitted. Retransmission of packet will be done when sender does not found ACK till it's Time Out. 0 votes 0 votes the_bob commented Sep 2, 2018 reply Follow Share Assuming that the transmission of the lost packets happens at the end (i.e., after the sender has finished transmitting all its packets), then can we have the following order ? (Packets given in italicized and bold indicate the lost packets.) 1 2 3 4 5 6 7 8 9 10 4 8 8 Every 4th packet is getting dropped (4, 8 and 8).. 0 votes 0 votes Please log in or register to add a comment.