Madeeasy workbook

Question

Q-21

Comments

I am gettig 2 .

What is the answer.??

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I don't know the answer.Please provide the way you solve.

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We try to make view equvalent .

Initial read

Updated read

Final write

Answer 1

There is no initial-read of data-item A.

write-read conflicts-

T1 -> T2

T3 -> T4

T5 -> T6

final-write of data-item A-

T5 only.

Since, final-write is T5 so T5,T6 should come at the last(we can't write it as T6,T5 cause in that case write-read conflict will get violated).

Either of (T1,T2) and (T3,T4) can come first.so,total 2 view-equal serial-schedules are possible.

T1 ,T2 ,T3 ,T4 ,T5 ,T6

T3 ,T4 ,T1 ,T2 ,T5 ,T6

Comments

Nice explanation.