gfg C pointer Basic

Question

Please explain solution in brief .

#include <stdio.h>
void f(char**);
int main()
{
    char *argv[] = { "ab", "cd", "ef", "gh", "ij", "kl" };
    f(argv);
    return 0;
}
void f(char **p)
{
    char *t;
    t = (p += sizeof(int))[-1];
    printf("%s\n", t);
}

A] ab    B] cd       C] ef     D] gh

Comments

Same question: https://gateoverflow.in/215449/c-programming

Answer 1

**p contains add of "ab"

According to OperatorPrecedence

1)  sizeof(int) = 4

2)  (p +=sozeof(int))  == (p = p +4)

              and p+4 is address of "ij"

3)  (p += sizeof(int))[-1]  mean "gh"

so t = gh