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+13 votes
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The minterm expansion of $f(P,Q,R) = PQ +Q \bar{R}+P\bar{R}$ is

  1. $m_2+m_4+m_6+m_7$
  2. $m_0+m_1+m_3+m_5$
  3. $m_0+m_1+m_6+m_7$
  4. $m_2+m_3+m_4+m_5$
asked in Digital Logic by Veteran (101k points)
edited by | 1.6k views

3 Answers

+23 votes
Best answer

$PQ + QR' + PR' = PQR + PQR' + PQR' + P'QR' + PQR' + PQ'R' $

$\quad= PQR + PQR' + P'QR' + PQ'R' (111 + 110 + 010 + 100)$

$\quad =m_7 + m_6 + m_2 + m_4$

Option A.


Alternatively,
Using K-map
 

answered by Veteran (357k points)
edited
0
Good Explanations
+3 votes
option A

=PQ(R+~R)+(P+~P)Q~R+P~R(Q+~Q)

on simplification we will get minterms as 2,4,6,7
answered by Active (1.3k points)
–2 votes
answer -(A)
answered by (85 points)


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