1 votes 1 votes Suppose that $x$ bits of user data are to be transmitted over $k-$hop path in a packet-switched network as a series of packets each containing $p$ data bits and $h$ header bits with $x>>(p+h)$. The bit rate of lines is $b$ bps and propagation delay is negligible.What is the time taken by the source to transmit total bits? $(p+h)x/b \hspace{0.1cm} bits$ $(p+h)x/pb \hspace{0.1cm} bits$ $px/b \hspace{0.1cm} bits$ $hx/pb \hspace{0.1cm} bits$ Computer Networks packet-switching + – Anil Ji asked May 23, 2018 edited May 29, 2018 by srestha Anil Ji 3.7k views answer comment Share Follow See 1 comment See all 1 1 comment reply roh commented Jul 15, 2020 reply Follow Share Here is asked about the time taken by source to upload the total packets. So, B should be the answer. 0 votes 0 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes Answer is wrong because asking about total time ,,answer is given in bits,,although acc. to me solution will be- Prateek Raghuvanshi answered May 24, 2018 selected May 31, 2018 by Anil Ji Prateek Raghuvanshi comment Share Follow See all 9 Comments See all 9 9 Comments reply Show 6 previous comments Anil Ji commented May 31, 2018 reply Follow Share its ok and thanks 1 votes 1 votes abhishekmehta4u commented May 31, 2018 reply Follow Share Prateek Nice explnation 1 votes 1 votes Prateek Raghuvanshi commented May 31, 2018 reply Follow Share Thanks 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes The total number of packets needed is x/p. The total of data+header works out to (p+h)x/p bits. The source takes (p+h)x/(pb) sec to transmit this. The forwarding of the last packet by intermediate routers on the way takes up (k-1)(p+h)/b sec. Adding up the two gives the time to clear the full pipe (that is, from start at source of the first bit of first packet to move out till the receipt of the last bit of the last packet at the destination). Total time = (p+h)x/(pb) + (p+h)(k-1)/b. KULDEEP SINGH 2 answered Jan 21, 2019 KULDEEP SINGH 2 comment Share Follow See all 0 reply Please log in or register to add a comment.