#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main(void)
{
pid_t pid = fork();
pid = fork();
pid = fork();
if (pid == 0)
{
fork();
}
fork();
return 0;
}
Total Number of Processes existing will be (Including how many parent and child process will be there) ?
Please See My Solution.
Every Fork statement will create a new child process and return 0 and we have a main process along with it.
So
First Fork statement when executes Creates $2$ Process -----------> $1$ child and $1$ parent of it.
Second fork will be executed by child and parent. So child will create an extra process and parent too so Total $4$ processes in which $2$ of each are parent and children.
Third Statement likewise ----------> Total $8$ processes($4$ child + $4$ parent)
Now the child process will execute fork so $4$ child process hence give rise to $4$ extra processes leading to total of $12$ processes.
in which total $8$ parent(including the previous $4$ and $4$ child process). Now these $8$ process($4$ child + $4$ parent which were created inside if statement) will also execute last fork which will give rise to $8$ extra process hence total of $20$ Processes ( $12$ parent and $8$ child)
and before if there were $4$ parent also which will execute outer fork statement giving rise to $4$ extra process so total $24$ Processes (12 Parent and $12$ child).
Please see my solution carefully and point out weather the number of parent and child were calculated correctly ?
