$f = S_0'S_1' R + S_0'S_1R' + S_0S_1'R' + S_0S_1R$
$\quad=Q'P'R + Q'PR' + QP'R' + QPR $
$\quad= Q'(P⊕R) + Q(P⊕R)' $
$\quad= Q⊕P⊕R = P⊕Q⊕R$
Doing truth value substitution,
$${\begin{array}{|cccc|c|}\hline
\textbf{P}& \textbf{Q}& \textbf{R}&\bf{f}& \bf{P \oplus Q \oplus R } \\\hline
0&0&0&0&0 \\ 0&0&1&1&1\\ 0&1&0&1&1\\ 0&1&1&0&0\\ 1&0&0&1&1\\ 1&0&1&0& 0 \\ 1&1&0&0&0\\ 1&1&1&1& 1\\ \hline
\end{array}}$$ Correct Answer: $B$