1)
$S_1 :$ Interpreters process program according to the logical flow of control through the program. $TRUE$
$ S_2: $ Interpreter translates and executes the error-free first instruction before it goes the second. $TRUE$
Interpreter goes line-by-line of the program & executes line by line.
$S_3 :$ Interpreter processing time is less compared to the compiler. $FALSE$
Compiler processing times is less than the Interpreter because Compiler scans and translates the whole program at a time.
$S_4:$ LISP and prolog are interpreted languages. $TRUE$
So, $\color{Maroon}{S_1,S_2,S_4}$ $\color{Maroon}{\text{ are True.}}$
∴ $\color{Green}{\text{Option D) will be the right option.}}$
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2)
We know that number of networks possible in Class B is = $2^{14}$
& Number of hosts possible in each network in class B is = $2^{16}-2$
Given that, Number of networks in class B are $2^{m}$ & number of hosts are $2^{n}-2$
∴ We can conclude that,
$2^m = 2^{14}$
Or, $m = 14$
& $2^n - 2 = 2^{16}-2$
Or, $n =16$
Now, option A) says that $3m=2n$; But $3 \times 14 \neq 2 \times 16$
option B) says that $7m = 8n$; But $7 \times 14 \neq 8 \times 16$
option C) says that $8m = 7n$; And $8 \times 14 = 7 \times 16$
option D) says that $2m = 3n$; But $2 \times 14 \neq 3 \times 16$
∴ $\color{Blue}{\text{Option C) 8m= 7n is the correct answer}}$