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The cyclomatic complexity of each of the modules A and B shown below is 10. What is the cyclomatic complexity of the sequential integration shown on the right hand side?

1. 19
2. 21
3. 20
4. 10

retagged | 3.7k views

Cyclomatic Complexity of module = Number of decision points + 1

Number of decision points in A = 10 - 1 = 9
Number of decision points in B = 10 - 1 = 9
Cyclomatic Complexity of the integration = Number of decision points + 1
= (9 + 9) + 1
= 19
by Boss (13.4k points)
selected

Cyclomatic complexity of A=B=10

Number of decision points in A = 10 ­-1 = 9
Number of decision points in B = 10- ­ 1 = 9
Cyclomatic Complexity of the integration = Number of decision points + 1 = (9 + 9) + 1 = 19

by Boss (32.1k points)
0
is there any other way? ... @shiva veteran
+1 vote
a) 19
by Loyal (5.2k points)

cyclometric complexcity = edges - nodes +2

i think, while joining two independent graph structures sequentially, an extra edge is appeared between them , so 10+10+1 =21

Ans A

by (317 points)

As we know their are several ways to find Cyclomatic complexity one of the is :

Cyclomatic complexity = Number of enclosed regions + 1

Here, +1 is because of count of external region

Therefore, Cyclomatic complexity of A is 10 (given) which means Number of enclosed regions + 1 external region

and Cyclomatic complexity of B is 10 (given) which means Number of enclosed regions + 1 external region

When we combine both the modules external region becomes same for both

Hence, 10 + 10 - 1 = 19

Option (A) is correct.

by Active (1.6k points)

1