479 views
0 votes
0 votes
Show that a simple graph is nonseparable iff for any two given arbitrary edges a circuit can always be found that will include these two edges.

Please log in or register to answer this question.

Related questions

0 votes
0 votes
0 answers
1
Ayush Upadhyaya asked Jun 8, 2018
450 views
Show that a graph G is non-separable iff every vertex pair can be placed in some circuit in G.
0 votes
0 votes
1 answer
2
#Rahul asked May 20, 2017
831 views
Suppose a single tennis tournament is arranged among n players and the number of matches planned is a fixed number e (where n-1 < e < n(n-1)/2 ).For sake of fairness,how ...
1 votes
1 votes
2 answers
3
Ayush Upadhyaya asked Jun 2, 2018
1,600 views
Is every regular graph of degree d(d$\geq$3) non-separable?If not, give a simple regular graph of degree 3 that is separable.
0 votes
0 votes
0 answers
4
Ayush Upadhyaya asked Jun 2, 2018
658 views
Prove that in a connected graph G a vertex v is a cut-vertex if and only if there exist two(or more) edges x and y incident on v such that no circuit in G includes both x...