$Q1$

To build **16k x 16 RAM**, we need 16x2=**32** number of 1k x 8 RAMs, arranged in **2 **columns of **16**. To select one of those chips from a row, we need $4$ 2x4 decoders. To select one of those 4 decoders, we need $1$** **more 2x4 decoder. We can use the **enable input** to select one of the columns of 1kx8 RAMs from 2. Thus total 2x4 decoders needed is $5$.

So the answer is **(B)**.

$Q2$

The 8085 flag register will look like this:

[SUB A => I don't know what this does, but let's move on., subtract A from A, which may result in zero altogether I guess ]

MVI B,(01)H => Stores the value **01** to B

DCR B => will decrement B to zero. Let's check the flag bits now:

$D7$ : sign flag : The result is 0, so sign flag is $0$.

$D6$: Zero flag : The result is 0, so zero flag is $1$.

$D5$: Not used.

$D4$: Auxiliary Carry flag : There is no carry from lower nibble to higher nibble, so this flag is set to $0$.

$D3$: Not used.

$D2$: Parity flag : since D0 is 0, for even parity, this flag should be $1$.

$D1$: Not used

$D0$: Carry flag : No carry, so this bit is set to $0$.

Contents of the flag register will now be 0100 0100 which is $(44)H$

So, The answer is **None of these**.