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A system uses FIFO policy for system replacement. It has $4$ page frames with no pages loaded to begin with. The system first accesses $100$ distinct pages in some order and then accesses the same $100$ pages but now in the reverse order. How many page faults will occur?

1. $196$
2. $192$
3. $197$
4. $195$
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When we access the $100$ distinct page in some order (suppose order is $1 2 3$....$100$) then total page fault occurs are $100$. And in last, frame contain the pages $100 99 98 97$. When we reverse the string $(100,99,98....1)$ then first four page will not cause the page fault bcz they already present in frame but the remaining $96$ page will cause $96$ page fault,so total page fault are $100+96=196$.

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$Page$ $fault = 100+96(reverse$  $order)=196$

+1 vote
Answer will be "196" first 100 page fault will occur then 4 page hit after that 96 page fault total =100+96

If you want to visualize how this mapping take small value and check

1)Lets take 5 district element and its reveverse then page fault 5(page fault) + 4(page hit)+1 (page fault)

Total page fault=6

2) let's take 10 district element and its reveverse then 10(page fault)+4(page hit) +6(page fault)

Total page fault=16
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