0 votes 0 votes The value of $\displaystyle{\lim_{x\to 0}}$ $\sin x \sin(\dfrac{1}{x})$ $\text{is 0}$ $\text{is 1}$ $\text{is 2}$ $\text{does not exist}$ Mathematical Logic integration + – jjayantamahata asked Mar 17, 2018 • edited Mar 17, 2018 by Sukanya Das jjayantamahata 670 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes option a Well see function sin(1/x) is bounded between [−1,1] and as limx→0 xsin(1/x) the value of x will also go to zero hence value of limit is 0 abhishekmehta4u answered Mar 17, 2018 • edited Mar 17, 2018 by abhishekmehta4u abhishekmehta4u comment Share Follow See all 3 Comments See all 3 3 Comments reply jjayantamahata commented Mar 17, 2018 reply Follow Share How ? please explain abhishekmehta4u. 0 votes 0 votes ankitgupta.1729 commented Mar 17, 2018 i edited by ankitgupta.1729 Mar 18, 2018 reply Follow Share bro A is correct...when we put x = 0 then it becomes 0*(any number between -1 and 1 ) = 0 bcoz range of sinθ is from -1 to +1 .. 0 votes 0 votes abhishekmehta4u commented Mar 17, 2018 reply Follow Share yes 0 should be the answer 1 votes 1 votes Please log in or register to add a comment.
0 votes 0 votes It is option B Akhilesh Singla answered Mar 17, 2018 Akhilesh Singla comment Share Follow See all 3 Comments See all 3 3 Comments reply abhishekmehta4u commented Mar 17, 2018 reply Follow Share lim x-->0 sin(1/x)/1/x is not equal to 1. 0 votes 0 votes Akhilesh Singla commented Mar 17, 2018 reply Follow Share Yeah, you are right. My mistake. Then it should be 0. 0 votes 0 votes jjayantamahata commented Mar 17, 2018 reply Follow Share GOOD ATTEMPT! 0 votes 0 votes Please log in or register to add a comment.