NO , number of table required for above diagram will be three not two .
one table $ E_2 R_1$ [ $\underline{AD}$ $F$]
second table $R_2 E_3$ [$\underline G H A$ ]
third table $E_1 [ \underline{A} B C]$
we cant merge $E_1$ with $R_2 E_3$ because relation $R_2$ has key G ,and A is not key of relation which will produce redudancy ,so we can't merge.total participation of ralation is given towards $E_1$ ,so participation will not arise but redudancy is still there . so we have to keep seperate $E_1$ .