JK Flip Flop - Unused States

Question

Comments

2 unused state 110 and 111, is it correct?

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$001\rightarrow 010\rightarrow 100\rightarrow 101$

i think 4 unused state , $000,011,110,111$

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my sequence came out to be 000->001->011->100->101->010->000
and 111->000
110->000

So, 2 unused states.

Answer 1

Assuming Q1=0,Q2=0 and Q3=0 initially, the sequence of output is like this:

 

As you can see from the table, six different states are possible => 000 -> 001 -> 010 -> 100 -> 101 -> 110 -> 000 (initial)

Therefore , the number of unused states = 2

So, the answer is 2.

 

Answer 2

only 2 unused state which is 3,7