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It's a simple "If----then" statement.

Hence, the formulation would be of type $A \rightarrow B$

Here, $A$ is   "xy=x for all y"...Or rephrasing, "For all y, xy = x"

Hence, $A$ = $\forall y (P(x,y,x))$

And $B$ is "$x = 0$"

So, "If xy=x for all y, then x =0" $\equiv$ $\forall y (P(x,y,x))$ $\rightarrow$ ($x = 0$)

You can check the above Propositional expression is Always True.
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$\forall y\exists x\left (\left (P\left ( x ,y,z\right )=x\right )\rightarrow\left ( xy=x \right )\Lambda \left ( x=0 \right ) \right )$
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