edited by
1,258 views
0 votes
0 votes

In a token ring network the transmission speed is $10^7$ bps and the propagation speed is 200 meters/ μs. The 1-bit delay in this network is equivalent to:
(A) 500 meters of cable.
(B) 200 meters of cable.
(C) 20 meters of cable.
(D) 50 meters of cable.

edited by

1 Answer

1 votes
1 votes
option (C) is correct

we know the conversion that bit delay/Bandwidth => delay in sec and delay in sec*velocity => delay in meter

here Bandwidth(B)=10^7 bps , number of bits =1

propagation speed =200 meter/microsecond means in 1 microsecond 200 meter distance can be covered

= >in 1 second distance covered =>200*10^6 meter

=>propagation speed=2*10^8 m/sec

from above conversion,

delay in meter = (bits/B)*v =>(1/10^7 )*2*10^8 =>20 meter

Related questions

0 votes
0 votes
0 answers
1
abhinowKatore asked Apr 24, 2022
751 views
In Computer networks, do we have token ring in Gate 2023 syllabus
0 votes
0 votes
0 answers
2
Na462 asked Dec 3, 2018
1,314 views
0 votes
0 votes
0 answers
3
Yazanotoom50 asked Dec 2, 2018
1,445 views
Determine the efficiency of a token ring with a data rate of 250Mbps, a ring latency of 120 µsec and 5000 bit packets. Assume M hosts want to transmit and each host hold...
2 votes
2 votes
0 answers
4
Samaa.qudah asked Nov 29, 2018
625 views
Determine the efficiency of a token ring with a data rate of 250Mbps, a ring latency of 120 µsec and 5000 bit packets. Assume M hosts want to transmit and each host hold...