Both the statements are equivalent. It is Null-quantification rule.
i.e. $\exists x(A \rightarrow P(x)) \equiv A \rightarrow \exists xP(x)$ ..(Where $A$ does not have $x$ as free variable)
So, the interpretation of both the statements is (assuming the domain is set of all real numbers) :
∀x((x!=0)→∃y(xy=100)) = For every $x$, if $x$ is non-zero then there exists some $y$ such that $xy$=100.