decoder

Question

how many total decoder  required ?

constructing 6*64 decoder using 4*16

Answer 1

total levels required = ⌈ $\frac{6}{4}$ ⌉ = 2

total decoders required of size 4 x 16 to generate 6 x 64 = $\frac{64}{16^{1}} + \frac{64}{16^{2}} = 4 + 1 = 5$

 

but in last level 12 o/p of 4 x 16 are wasting... Therefore u can make one 6 x 64 with the help of four 4 x 16 and one 2 x 4.

Comments

@akash

but question is for $6\times 64$ and u r calculating for 64 only?

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@srestha mam, 6 x 64 is completely one decoder ( 6 i/p and 64 o/p ) . There is no separate decoders as 6 and 64.

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Number of $'N'$ bit $\text{MUX/DEMUX/DECODER/ENCODER}$ to construct $'M'$ bit $\text{MUX/DEMUX/DECODER/ENCODER}$ required is$:\left\lceil\dfrac{M-1}{N-1}\right\rceil$