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+9 votes
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The determinant of the matrix $\begin{bmatrix} 6 & -8 & 1 & 1 \\ 0 & 2 & 4 & 6 \\ 0 & 0 & 4 & 8 \\ 0 & 0 & 0 & -1 \end{bmatrix}$

  1. $11$
  2. $-48$
  3. $0$
  4. $-24$
asked in Linear Algebra by Veteran (59.7k points)
edited by | 586 views

1 Answer

+20 votes
Best answer
As the given matrix upper traingular matrix, determinant will be the product of main diagonal elements.

$det(A) = 6*2*4* -1 = -48.$

Similar concept can be appliead, if Matrix is lower triangular or Diagonal Matrix.
answered by (233 points)
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