v = 2 * 10^8 mps
B = 100 Mbps
d = 1000 m (between A and E)
station A 1000m station E
Tp = 1000/2 * 10 ^8 sec
at t = 0 Both start transmitting data
at t = Tp / 2 collide data packet (in middle collide data )
at t = Tp Both senesce collision
so Station A transmit data = Tp time
transmitted data = Tp * B(bandwidth)
= (1000/2 * 10 ^8)*(100 * 10^6) bit
= 500 bits (by solving above question)
= 500 / 8 Bytes = 62.5 bytes
So , correct option (A)