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| 135 views

+1 vote

Basics of J-K Flipflop when J=K=1 :-

CLK=0 ===> previous values as o/p

CLK=1 ===> toggle the previous values as o/p

∴ Q0N = Q0'          ( CLK )   value changed from 1 --> 0 ( Because -ve edge triggering )

∴ Q1N = Q1'  when ( Q0N and CLK )   value changed from 1 --> 0 ( Because -ve edge triggering )

= Q1  otherwise

for avoiding confusion, take a temporary clock  as  Q0N and CLK

∴ Q2N = Q2'  when ( Q0N and Q1N and CLK ) value changed from 1 --> 0 ( Because -ve edge triggering )

= Q2  otherwise

for avoiding confusion, take another temporary clock  as  Q0N and Q1N and CLK

By the above information

Q0     Q1     Q2

-----------------------

0        0        0

1        0        0   ( after applying 1st clock pulse )

0        1        0   ( after applying 2nd clock pulse )

1        1        0   ( after applying 3rd clock pulse )

0        0        1   ( after applying 4th clock pulse )

1        0        1   ( after applying 5th clock pulse )

After 5 clk pulses, 101 (Q0,Q1,Q2) and Y=0 (Q0⊕Q1⊕Q2)

by Veteran (64.6k points)
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Thanks!
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what i m asking is that i am getting 2nd flip flop as on on doing like as marked with arrow after toggling the Q0

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∴ Q1N = Q1'  when ( Q0N and CLK )   value changed from 1 --> 0 ( Because -ve edge triggering )

= Q1  otherwise

for avoiding confusion, take a temporary clock  as  Q0N and CLK

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WHAT TO DO WITH THIS AND CIRCUITRY BECZ IF CONSIDERInG IT AND FOLLOWING SIMPLE PROCEDURE AS PER THE GIVEN CIRCUIT ...CAN U PROVIDE OUTPUTS OF ALL THE AND GATES IN EACH CLOCK PULSE.

AND HOW I AM GETTING SAME ANSWER OR SAY SEQUENCE IS JUST BY CONSIDERING THE CONCEPT OF clock of flipflop is the output of previous flipflop.
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