1 votes 1 votes RST 7.5 interrupt in 8085 microprocessor executes the interrupt service routing from interrupt vector location 0000H 0075H 003CH 0034H CO and Architecture gate1997 co-and-architecture 8085-microprocessor out-of-syllabus-now + – Kathleen asked Sep 29, 2014 retagged Nov 13, 2017 by Arjun Kathleen 3.0k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
6 votes 6 votes RST 7.5 Location will be 7.5*8 = 60. // 8085 is 8 bit processor 60 in hexadecimal will be 003C H Digvijay Pandey answered Jun 9, 2015 Digvijay Pandey comment Share Follow See 1 comment See all 1 1 comment reply mohit jangid 1 commented Dec 25, 2015 i edited by mohit jangid 1 Dec 26, 2015 reply Follow Share Why multiply with 8 bit? We should multiply by IVT Entry size in bytes. Isn't it? 0 votes 0 votes Please log in or register to add a comment.