Fog and gof function

Question

Comments

fog(x) = f(g(x)) = $\frac{\frac{x}{1+x}}{1-\frac{x}{1+x}} = x$ 

(fog)^-1x = $\frac{1}{x}\times x = 1$

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I think you are doing mistakes . We have to put g(x) value in f(x).

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I am getting option a

Answer 1

I think the answer is b