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Question 4 : Find the largest number which divides 64, 136 and 238 to leave the same remainder in each case.
Solution : To find the required number, we need to find the HCF of (136-64), (238-136) and (238-64), i.e., HCF (72, 102, 174).
72 = 23 x 32
102 = 2 x 3 x 17
174 = 2 x 3 x 29
Therefore, HCF (72, 102, 174) = 2 x 3 = 6
hence, 6 is the required number.

why we find hcf of difference between pairs of number

asked in Numerical Ability by Active (1.9k points) | 56 views
+1
Basics of HCF :-

HCF(a,b,c) = HCF(|a-b|,|b-c|,|c-a|).

 

for getting lower value, they use that formula that's it,

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