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30. A system uses the Stop-and-Wait ARQ Protocol. If each packet carries 1000 bits of
     data, how long does it take to send 1 million bits of data if the distance between the
     sender and receiver is 5000 KIn and the propagation speed is 2 x 108 m? Ignore transmission,
     waiting, and processing delays. We assume no data or control frame is lost
     or damaged.

My solution -

Propagation time = Distance / speed = 5000 * 10^3 / (2 * 10^3) = 25 ms

RTT = 2 * Propagation time = 2 * 25 = 50 ms

Total packets = 1 million bits / 1000 bits = 10^3 packets

1 packets takes 50 ms

10^3 packets take time = 10^3 * 50 ms = 50 s

so answer is 50 s.

Am i right or wrong? if wrong, please correct me with right approach.
asked in Computer Networks by (57 points) | 47 views
0
Yes. It is correct.

In  Stop-and-Wait ARQ Protocol,

Total time taken by n-packet = n*time taken by one packet

& time taken by one packet = RTT
0
Yes the procedure is correct.
0
Is there bandwidth given?

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