Made easy workbook

Question

A System uses a two level page table has 2^12 bytes pages and 32 bit virtual adresses .The first 8 bit of the address serve as a index into the first level page table.For 64 bit virtual addresses,a 4kb page size and 256 mb of RAM an inverted page table requires

A)2^40 entries.              B)2^52 entries

C)2^16 entries.               D)2^78 entries

Answer 1

no.of frames = size of RAM / PAGE size = 2¹⁶

entries of inverted page table = no.of frames = 2¹⁶

Answer 2

In inverted page table .

Number of frame = number of entries in inverter page table.