no.of frames = size of the physical address/ page size
page table entry= 2 bytes = 16 bits
frame number is less than or equal to 16-2=14 and greater than or equal to 7
option a: 64 KB ==> bits requried for fame no = 16 - 13 = 3
option b: 64 MB ==> bits requried for fame no = 26 - 13 = 13
option c: 64 GB ==> bits requried for fame no = 36 - 13 = 23
option d: 8 MB ==> bits requried for fame no = 23 - 13 = 10
option b or d is correct
