C program output

Question

Comments

a[0]='w' and a[5]='\0'

In the 1st iteration i=0 and j=5, a[i++]=a[j--]

So after the 1st loop, a[0]=a[5] and i=1 ,j=4.

I.e. a[0]='\0'. When we try to print a ,since it starts with null character now so it is assumed to be the end of a string(as null character indicates the end of string). All the other characters after that won't be considered as part of a. So null string will be printed.

Answer 1

a[6] = 

'w'

'o'

'r'

'l'

'd'

'\0'

 

after executing the loop a[6] look like as

'\0'

'd'

'l'

'l'

'd'

'\0'

 

 

printf function stops printing the elements whenever it scans a null character.

therefore output is NULL String (nothing printed)

Comments

Shaik Masthan won't a look like ---> '\0' 'd' 'l' 'l' 'd' '\0'  ? Please confirm

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it's look like as '\0' 'd' 'l' 'l' 'd' '\0'  is correct.

 

previously, i mistakenly swapped them, i already updated