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In question 13 Can we directly apply the formulae or we have to change the bandwidth(if have to change then how can we change)

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bandwidth=400 Hz=400bps

(S/N)_{ratio} =7 db

we know that (S/N)_{ratio}=10*log_{10}(signal power/noise power) db

=>7=10*log_{10}(signal power/noise power)

(signal power/noise power)=5.011

maximum data rate(capacity)=B*log_{2}(1+(signal power/noise power))

=>400*log_{2}(1+(5.011))=1035.042 bps.

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