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In question 13 Can we directly apply the formulae or we have to change the bandwidth(if have to change then how can we change)

asked ago in Computer Networks by (167 points) | 29 views

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bandwidth=400 Hz=400bps

(S/N)ratio =7 db

we know that (S/N)ratio=10*log10(signal power/noise power) db

=>7=10*log10(signal power/noise power)

(signal power/noise power)=5.011

maximum data rate(capacity)=B*log2(1+(signal power/noise power))

=>400*log2(1+(5.011))=1035.042 bps.


answered ago by Active (2.9k points)

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