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How to solve it?Q 5

+1 vote
T1 carrier has a data rate of 1.544Mbps. According to Shannon's theorem, the maximum data rate = Blog2(1+S/N) where B is the bandwidth and is equal to 50kHz.

1.544Mbps =50log2(1+S/N)

=2^(1.544M/50k)-1=1.976e9=92.9581dB~93db
0
Max capacity is in Mbps and bandwidth is in kHz how we put this ??how can we compare Mbps with khz