Effective Access Time

Question

 

Answer 1

hit ratio is 90% so emat=.9*(3+50)+.1(3+150)=15.3+47.7=63 ns 150 because 1 mm access for 1 level, 1 mm for second level and last one to access the desired object here mm is memory access

Comments

since all level page table reside in memory hence for 2 level page table memory reference is 3 and so on

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Ohk, in this Question " Consider a paging hardware with a TLB. Assume that the entire page table and all the pages are in the physical memory. It takes 10 milliseconds to search the TLB and 80 milliseconds to access the physical memory. If the TLB hit ratio is 0.6, the effective memory access time (in milliseconds) is "

Here when there is miss 2 Memory access is required Right ?

1 for page table access to get frame number and second for accessing the frame in main memory isn't it?

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yes