# UGCNET-July-2018-II: 99

1.4k views

Simplify the following using $\text{K}$ – map :

$F(A, B, C, D) = \Sigma (0, 1, 2, 8, 9, 12, 13)$

$d(A, B, C, D) = \Sigma (10, 11, 14, 15)$

$\text{d}$ stands for don't care condition.

1. $A+\bar{B} \bar{D} +BC$
2. $A+\bar{B} \bar{D} + \bar{B} \bar{C}$
3. $\bar{A} + \bar{B} \bar{C}$
4. $\bar{A} + \bar{B} \bar{C} + \bar{B} \bar{D}$

edited
0
B) $A + \bar{B} \bar{C} + \bar{B} \bar{D}$

Option B

## Related questions

1
385 views
In $RS$ flip-flop, the output of the flip-flop at time ($t+1$) same as the output at time $t$, after the occurrence of a clock pulse if : $S$=$R$=$1$ $S$=$0$, $R$=$1$ $S$=$2$, $R$=$0$ $S$=$R$=$0$
Match the terms in List-I with the options given in List-II List - I List - II a Decoder i 1 line to $2^n$ lines b Multiplexer ii n lines to $2^n$ lines c De multiplexer iii $2^n$ lines to 1 line iv $2^n$ lines to $2^{n-1}$ ... $lines} \\\hline \end{array}$ a-ii; b-i; c-iii a-ii; b-iii; c-i a-ii; b-i; c-iv a-iv; b-ii; c-i