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Perform the following operation for the binary equivalent of the decimal numbers $(-14)_{10}+(-15)_{10}$. The solution in 8 bit representation is

  1. 11100011
  2. 00011101
  3. 10011101
  4. 11110011
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3 Answers

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2 votes

To add 2 negative binary numbers, change them into 2's complement form, and then add it.
So in this case,

  • $-(14)_{10}$ = $00001110_2$ 
  • $-(15)_{10}$ =$00001111_2$

2's complement of $(00001110)_2 \longrightarrow  11110001+1 = 11110010$
2's complement of $(00001111)_2 \longrightarrow 11110000+1 = 11110001$

add them to get the solution:

$(11110010)_2$ + $(11110001)_2= (11100011)_2$

Option $(A)$ is correct.

edited by
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Option A 11100011
 

(−14)10+(−15)10  

(−29)10 

=    1        1     1      0    0    0   1   1
   -128    64    32    16   8   4   2   1

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