UGC NET CSE | July 2018 | Part 2 | Question: 93

Question

Match the terms in $\textbf{List-I}$ with the options given in $\textbf{List-II}$ :

$\begin{array}{clcl}  & \textbf{List-I} & & \textbf{List-II}\\ \text{(a)} & \text{Decoder} &\text{(i)} & \text{1 line to $2^n$ lines} \\ \text{(b)} & \text{Multiplexer} & \text{(ii)} & \text{n lines to $2^n$ lines} \\ \text{(c)} & \text{De multiplexer} & \text{(iii)} &\text{$2^n$ lines to 1 line} \\ &&\text{(iv)}& \text{$2^n$ lines to $2^{n-1}$ lines} \\ \end{array}$

$\textbf{Code :}$

• A. $\text{(a)-(ii); (b)-(i); (c)-(iii)}$
• B. $\text{(a)-(ii); (b)-(iii); (c)-(i)}$
• C. $\text{(a)-(ii); (b)-(i); (c)-(iv)}$
• D. $\text{(a)-(iv);(b)-(ii); (c)-(i)}$

Comments

Decoder - n lines to $2^n$ lines

Multiplexer - 1 line to $2^n$ lines

DeMux - $2^n$ lines to 1 line

option A is correct.

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Multiplexer is Many to 1

Answer 1

Option B. a-ii; b-iii; c-i

Decoder = n to 2^n
Mux = Many to One i.e. 2^n to 1
De Mux = One to Many i.e. 1 to 2^n