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Match the following in List - I and List-II, for a function $f$:

 List - I List - II a $\forall \: x \: \forall \: y \: (f(x)=f(y) \rightarrow x=y)$ i Constant b $\forall \: y \: \exists \: x \: (f(x) =y)$ ii Injective c $\forall \: x \: f(x)=k$ iii subjective
1. a-i, b-ii, c-iii
2. a-iii, b-ii, c-i
3. a-ii, b-i, c-iii
4. a-ii, b-iii, c-i
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Option A : For all x and for all y, if f(x)=f(y) then x=y implies it is a one-to-one function or injection.

Option B : For all y, there exists an x means all elements in the co-domain must be mapped to some element in the domain which implies it is an onto function or surjection .

Option C : For all f(x)=k (k≠0) implies a straight line parallel to x axis i.e.constant.
answered by Loyal (7k points)
0
Ans D

a - ii
b - iii
c -  i

1