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Match the following in $\textbf{List-I}$ and $\textbf{List-II}$, for a function $f$ :

$\begin{array}{clcl}  \text{} & \textbf{List-I} & & \textbf{List-II} \\ \text{(a)} & \text{$\forall \: x \: \forall \: y \: (f(x)=f(y) \rightarrow x=y)$} & \text{(i)} & \text{Constant} \\ \text{(b)} & \text{$\forall \: y \: \exists \: x \: (f(x) =y)$} & \text{(ii)} & \text{Injective} \\ \text{(c)} & \text{$\forall \: x \: f(x)=k$} & \text{(iii)} &\text{Surjective} \\  \end{array}$

$\textbf{Code :}$

  1. $\text{(a)-(i), (b)-(ii), (c)-(iii)}$
  2. $\text{(a)-(iii), (b)-(ii), (c)-(i)}$
  3. $\text{(a)-(ii), (b)-(i), (c)-(iii)}$
  4. $\text{(a)-(ii), (b)-(iii), (c)-(i)}$
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Option A : For all x and for all y, if f(x)=f(y) then x=y implies it is a one-to-one function or injection.

Option B : For all y, there exists an x means all elements in the co-domain must be mapped to some element in the domain which implies it is an onto function or surjection .

Option C : For all f(x)=k (k≠0) implies a straight line parallel to x axis i.e.constant.

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