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Here L1(access time)=30nsec

L2(access time)=30*8=240nsec(as its 8 times slower than L1)

Avg(access time)=L1+40=30+40=70nsec

Avg(access time)=Hit in L1 i.e H1 * L1( access time)  +   Miss in L1 i.e(1-H1)   * Hit in L2 i.eH2*   L2(access time)

Here H2 hit ratio will be 1 becz page not found in L1 will always be found in L2 memory

70=H1*30+(1-H1)*1*240

H=0.809=0.81
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