598 views
2 votes
2 votes
Relation $R=(L, M, N, O, P)$

$R$ is decomposed into $R_{1} = (L, M, N, P)$ and $R_{2} = (M, O).$

for $R_{1}$ dependencies are

$P->L, L->MN$

$1)$What are keys for $R_{1}$?

$2)$What normal form it holds?

3 Answers

Best answer
2 votes
2 votes
Key for R1 = P

as P - > { P, L, M, N }

It's in 2nd Normal Form, as we don't have Partial Dependency but we have Transitive Dependency.
selected by

Related questions

1 votes
1 votes
2 answers
1
1 votes
1 votes
1 answer
3
Shefali asked Jul 23, 2015
4,838 views
The answer given is YES. But how is the dependency C - DE preserved in this decomposition?
0 votes
0 votes
1 answer
4