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Made Easy programming and DS

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A(n) { if(n<1) return 1; else return A(n-2) + B (n-1); } B(n) { if(n<=1) return 1; else return B(n-1) + A(n-2); } What is the output for A(6)? Please show how the recursion is working here along with the solution.
A(n){if(n<1)return 1;elsereturn A(n-2) + B (n-1);}B(n){if(n<=1)return 1;elsereturn B(n-1) + A(n-2);}What is the output for A(6)?Please show how the recursion is working h...
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Consider the following nested recursive function: A(m,n)= n+1 if m=0, A(m-1,1) if n=0, A(m-1,A(m,n-1)) otherwise. What is the output of A(2,3)?
Consider the following nested recursive function: A(m,n)= n+1 if m=0, A(m-1,1) if n=0, A(m-1,A(m,n-1)) otherwise.What is the output of A(2,3)?
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