C Programming

Question

void main(main)
{
  int i,a[8]={000,001,010,011,100,101,110,111};
  for(i=0;i<8;i++)
  printf("%d",a[i]);
}

 
$\text{o/p is}$ $0,1,8,9,100,101,110,111$ $\text{Pls Explain}$

Comments

when you starts a value with 0 ===> it stored in Octal Form

010 gives = (0*8²) + ( 1 * 8¹) + ( 0 * 8⁰) = 0+8+0 = 8

 

For more information, read escaping characters in C.. https://en.wikipedia.org/wiki/Escape_sequences_in_C

Answer 1

This happens because an integer digit preceded by 0 is interpreted as an octal number. First Four initialization in your array starts with 0 so by default Compiler takes it in octal form and then converts into integer. So as 000,,001, 010,011, converted into 0,1,8,9.